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problem is a corner with what appears to be a radius of 10 in.

2006-12-17 16:31:47 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

if it is a quarter circle than it will have quarter the circumeference of the circle + 2 radii for center to vertical and center to horizontal

1/4(2Pir) +2r= 5Pi +20

2006-12-17 16:34:00 · answer #1 · answered by Zidane 3 · 0 0

D8335e3d58db83c2fdc777a379bc66fbameter = d Rad8335e3d58db83c2fdc777a379bc66fbus = r C8335e3d58db83c2fdc777a379bc66fbrcumference = 28335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fbr G8335e3d58db83c2fdc777a379bc66fbven: Per8335e3d58db83c2fdc777a379bc66fbmeter of total C8335e3d58db83c2fdc777a379bc66fbrcle = C8335e3d58db83c2fdc777a379bc66fbrcumference d = (pi)x Solut8335e3d58db83c2fdc777a379bc66fbon: d = 2r, hence, r=d/2; r = (pi)x/2, subst8335e3d58db83c2fdc777a379bc66fbtut8335e3d58db83c2fdc777a379bc66fbng (pi)x for d Per8335e3d58db83c2fdc777a379bc66fbmeter of total C8335e3d58db83c2fdc777a379bc66fbrcle = 28335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb/28335e3d58db83c2fdc777a379bc66fb = 8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb Per8335e3d58db83c2fdc777a379bc66fbmeter of Quarter C8335e3d58db83c2fdc777a379bc66fbrcle = 8335e3d58db83c2fdc777a379bc66fb1/48335e3d58db83c2fdc777a379bc66fb Per8335e3d58db83c2fdc777a379bc66fbmeter of total C8335e3d58db83c2fdc777a379bc66fbrcle by subst8335e3d58db83c2fdc777a379bc66fbtut8335e3d58db83c2fdc777a379bc66fbon, Per8335e3d58db83c2fdc777a379bc66fbmeter of Quarter C8335e3d58db83c2fdc777a379bc66fbrcle = [8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb8335e3d58db83c2fdc777a379bc66fb]/4

2016-12-30 14:16:13 · answer #2 · answered by gerda 4 · 0 0

For a quarter circle:

Assume the radius of this quarter circle is r. Then, to get the perimeter, it would be

P = (vertical slice) + (horizontal slice) + 1/4 around a full circle.

The vertical and horizontal slices both represent the radius, so they are both r. To obtain the perimeter around a quarter circle, you need to calculate 1/4 the circumference of a circle. Therefore, if

C = 2(pi)(r), then
1/4 C = (1/4) 2(pi)(r), or
1/4 C = (1/2) (pi)(r)

Therefore, since

P = (vertical slice) + (horizontal slice) + 1/4 around a full circle

then

P = r + r + (1/2)(pi)(r). This can be simplified to
P = 2r + (1/2)(pi)(r)
P = 2r + [(pi)(r)]/2, which if we put under a common denominator,

P = [4r + pi(r)]/2, or
P = (r/2)(4 + pi)

Since the radius is given to be r = 10, then

P = (10/2)(4 + pi), or
P = 5(4 + pi)

I'll leave it up to you to use a calculator.

2006-12-17 16:38:20 · answer #3 · answered by Puggy 7 · 0 0

Formula you are looking for is:

p = (c/4) +20

where p = perimeter
c = circumference
and 20 is the two radii (of a quarter circle)

circumference is divided by 4 as you only want a quarter

answer is (tp 1dp) 35.7 in

2006-12-17 16:41:54 · answer #4 · answered by darceypollard 2 · 0 0

It will be 2r + Pi r/2 = 20 + 110/7 = 35.7 in

2006-12-17 16:42:00 · answer #5 · answered by Srinivas c 2 · 0 0

i assume we are talking about 1/4 of a circle...

C = 2 pi r

1/4 C = 1/2 pi r = 5pi

5pi + 10 + 10

so it's 20 + 5pi = 35.7 in

2006-12-17 16:35:57 · answer #6 · answered by VZ 2 · 0 0

Circ = 2 * PI * r
= 6.28 * 10 = 62.8
Since we have a quarter, divide by 4

2006-12-17 16:36:52 · answer #7 · answered by Renaud 3 · 0 0

(1/4)*2pir + r
1/4*2*3/14*10 +2*10
=35.7 in

2006-12-17 16:34:32 · answer #8 · answered by raj 7 · 0 0

P = 2πR/4 + 2R = 2R(1 + π/4)
P = 2*10(1+3.14159/4)
P ≈ 35.7 in.

2006-12-17 16:50:56 · answer #9 · answered by Helmut 7 · 0 0

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