How can I determine the surface area an object 3 1/2 in. in diameter and 6 in. high to label a can?

Answer 1

The area of the label is only the area of the curved surface only, excluding the top and bottom circle. So it's equal to the circumference of the base times the height. You have the diameter, d, and the height, h. The circumference is d*pi and the surface area in question is h*d*pi.

Answer 2

Surface area
= surface area around + surface areas of two circular faces
= (pi)(diameter)(height) + 2 (pi)(diameter)^2 /4
= (pi) x 3 1/2" x 6" + (1/2)(pi) (3 1/2")^2
= 21 (pi) + 49/8 (pi)
= 24 1/8 (pi) in^2
This should be enough; but you may substitute pi = 3.14159 and use your calcultor

Answer 3

Since you are interested in putting on a label, that would be the surface area on the side of the can, excluding the top and bottom.

Let
Diameter d = 3.5 in
Height h = 6 in

The side surface area = πdh = π*3.5*6 = 65.97 cm^2

Answer 4

let pretend for a moment .....


If you cut the can and lay it flat it would be a rectangle measuring
3 .5 " wide by 6 " long then it would be ease to find the area let do it

A = l x w

where A is the area
l is the length
w is the wide


A = 6" x 3.5 "

A = 21 sq. in.

Answer 5

d=3.5
r=d/2=1.75
A=πr^2*h=π*6*1.75^2=57.7in^2