can someone solve this problem? It is very urgent. Thanks in advance
2006-12-17 14:04:10 · 11 answers · asked by bts_22 1 in Science & Mathematics ➔ Mathematics
I am sorry the problem looks like this
x 2
--------------- - --------------
x-2 x-2
2006-12-17 14:14:13 · update #1
Nevermind... its almost immpossible to type equations on a keyboard. Thanks anyway.
2006-12-17 14:15:30 · update #2
I guess must be "hammer time"
x/(x-2) - 1
[x-(x-2)]/(x-2)
2/(x-2) ....which is the final answer!
2006-12-17 14:08:24 · answer #1 · answered by alrivera_1 4 · 1⤊ 0⤋
(x/(x - 2)) - ((x - 2)/(x - 2))
(x - (x - 2))/(x - 2)
(x - x + 2)/(x - 2)
2/(x - 2)
2006-12-18 00:01:56 · answer #2 · answered by Sherman81 6 · 1⤊ 0⤋
((x)-(x+2))/(x-2)
= 2/(x-2)
2006-12-17 22:09:30 · answer #3 · answered by spencer w 1 · 1⤊ 0⤋
x-(x-2)/(x-2)
x-x+2/(x-2)
2/x-2
2006-12-18 01:00:35 · answer #4 · answered by Anonymous · 1⤊ 1⤋
From the way that's written...
2/(x-2)
that's elementary school math.
2006-12-17 22:08:56 · answer #5 · answered by womfalcs7 2 · 1⤊ 0⤋
Is that it? Is it equal to something like (x)/(x-2)-(x-2)/(x-2)=0. Answer this, then I can help you.
2006-12-17 22:09:20 · answer #6 · answered by iceprincessk7 2 · 0⤊ 1⤋
[(x)/(x - 2)] - [(x - 2)/(x - 2)]
They both have the same denominator
So it is just
[x - (x - 2)]/(x - 2)
(x - x + 2)/(x - 2)
2/(x - 2)
2006-12-17 22:09:13 · answer #7 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
x/(x - 2) - 2/(x - 2)
Since they are fractions of the same denominator, then we can bind them into one fraction.
(x - 2)/(x - 2)
Since a/a = 1, therefore
= 1
^_^
2006-12-18 03:34:36 · answer #8 · answered by kevin! 5 · 0⤊ 2⤋
(x)/(x-2)-(x-2)/(x-2)
x/(x-2) - 1 =
x = 1(x - 2)
x - x = -2
zero
<::>
2006-12-17 22:08:24 · answer #9 · answered by aeiou 7 · 0⤊ 2⤋
OK, here is the answere as I understand you.
1-x+2x (to the -1 power)
2006-12-17 22:21:49 · answer #10 · answered by tennacious_c 2 · 0⤊ 2⤋