Solve. 80 = 10x?

Question

A long-distance phone call costs $0.25 for the first minute and $0.10 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $5.

A electronics store wants to order at least 3 times as many DVD players as VHS players. Write an inequality expressing this relationship.

Answer 1

Don't worry about it. It doesn't matter if you pass math or not. You can still get a fine job in the janitorial services.

Answer 2

To solve 80=10x, divide both sides by 10, and you get 8=1x, or x=8

For the second, 5 >= the cost of the call, right? Well, if the length of the call is "n" minutes, then the call costs .25 + (n-1)*.1
So .25+.1*(n-1) <= 5
(you can simplify this equation by expanding the terms).

For the third, if d = the number of DVDs and V is the number of VHS's, then V*3 <= D

Answer 3

Let t be the time in number of minutes,
then 0.25 + 0.10t <= 5 .
We need to add t >= 0 to make sense.
For the case that t can have any real solutions, t <= 57.5.
If t can only have integral solutions , t <=57.

Let x be the number of DVD players ordered, y be the number of VHS players ordered.
Then x / y >= 3 ,
or equivalently x >= 3y.
Subject to x and y are non-negative integers.

Answer 4

.25 + .10x <= 5 for first prob.

Do you have to solve it? If so, mult. through by 100, then
25 + 10x <= 500
10x <= 475
x <= 47.5
So 47 minutes is the limit.

d >= 3v where d = dvd players and v = vhs players.

Answer 5

.25+.1(x-1)<5 and x=the number of minutes
x<48 min

3x>x and x=number of VHS players

Answer 6

80=10x
the answer is x=8

Answer 7

80=10x
x=8

500>=15+10m
485>=10m
m<=48.5
since they charge a full minute for ant fraction
m<=48 minutes

dvd>=3vhs

Answer 8

yes, x=8

Answer 9

x=8
10x8=bumbumbummmmmm 80

Answer 10

X=8, so easy.