2006-12-17 12:25:07 · 5 answers · asked by Sarah S 1 in Science & Mathematics ➔ Mathematics
log(7x+1)=log(4x+16) then 7x+1=4x+16
7x-4x=16-1
3x=15 => x=5 is solution.OK???
2006-12-17 23:39:54 · answer #1 · answered by grassu a 3 · 0⤊ 0⤋
Since the log base is a in both cases, you can equate what you are taking the log of.
loga(7x+1)=loga(4x+16)
7x + 1 = 4x + 16
3x = 15
x = 5
2006-12-17 12:43:16 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
well, simple: since both sides of the equal sign consists of log a, you can simply cancel the 'log a'. Then, what's left should be easy.
7x+1=4x+16
3x=15
x=5
2006-12-17 12:30:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
log(a)(7x + 1) = log(a)(4x + 16)
7x + 1 = 4x + 16
3x = 15
x = 5
2006-12-17 16:40:49 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
Here my answer
7x+1=4x+16
7x-4x=16-1
3x=15
x=5
2006-12-17 12:34:32 · answer #5 · answered by Anis Z 1 · 0⤊ 0⤋