2006-12-17 11:52:44 · 4 answers · asked by celticevening 1 in Science & Mathematics ➔ Mathematics
The review answer sheet gives r=2.38
I need to see the work, I cannot get this answer. Thanks.
2006-12-17 21:00:58 · update #1
5 ^2r-3 =17
(2r-3)ln 5=ln 17
2r-3=ln 17 / ln 5
2r=3+ln 17/ ln 5
r=(3+ln 17 / ln 5)/2=5 ^2r-3 =3.260
2006-12-17 11:55:47 · answer #1 · answered by yupchagee 7 · 15⤊ 0⤋
5 ^2r-3 =17
<=> 5^2r = 20
<=> 2r = log base 5 of (2^2 * 5)
<=> 2r = 1 + 2log base 5 of 2
<=> r = 1/2 + log base 5 of 2
2006-12-17 17:50:40 · answer #2 · answered by James Chan 4 · 0⤊ 0⤋
You have too many questions..
Once again im assuming 2r - 3 is the argument and 5 is the base.
This can be written as 5^17 = 2r - 3
and whoah thats a big number so you can solve it.
2006-12-17 11:56:12 · answer #3 · answered by laffytaffychick13 1 · 0⤊ 0⤋
Use parenthesis so that you can understand your question
Ana
2006-12-17 11:57:56 · answer #4 · answered by Ilusion 4 · 0⤊ 0⤋