I got the equations and the solution, now how do I balance?
•HgCl2 + Na2CO3 = 2NaCl + HgCO3
•No2(Co3) + Pb(No3)2 = Pb(Co3) + No2(No3)2
•No2(Co3) + KI = No2I + K(Co3)
•Pb(No3)2 + Na2(SO4) = Pb(SO4) + Na2(No3)2
•BaCl2 + Na2(SO4) = Ba(SO4) + Na2Cl2
•CuCl2 + No2(Co3) = Cu(Co3) + No2Cl2
•CuCl2 + KI = CuI + KCl2¬
thank you
2006-12-17 10:41:34 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
What the.... u sure?
2006-12-17 10:49:06 · update #1
well since they are balanced, can u atleast check if they are right?
2006-12-17 10:50:22 · update #2
As you can see, everything is balanced.
Take for example,
HgCl2 + Na2CO3 --> NaCl + HgCO3
The above equation is not balanced. It is very simple when the equation is written for you and all you have got to do is just write the coefficent in front.
As you can see, there is only one Hg, so your right side should only consist of one Hg. Then you look at the Cl, there are 2 of them and that means you need 2 at the other side, so you would mentally tell yourself to get ready to add a 2 in front of NaCl if you see 2 Na. Moving on to the next reactant, you see 2 Na, this means that you can add 2 in front of the NaCl because you have 2 of Na and 2 of Cl. CO3 is 1 which is same as your Hg. So, no coefficent is needed to add on. Hence, you get...
HgCl2 + Na2CO3 --> 2NaCl + HgCO3
It is just a comparison of coefficent and then balancing them out by just counting the number of it.
BTW they are right.
2006-12-17 10:52:26 · answer #1 · answered by PIPI B 4 · 0⤊ 0⤋
They are already balanced...are you trying to ask what kind of reaction is occurring or something?
2006-12-17 10:48:34 · answer #2 · answered by CC 2 · 0⤊ 0⤋
MadNet I saw you on the news today...!!
â http://www.osoq.com/funstuff/extra/extra03.asp?strName=MadNet
2006-12-17 10:53:54 · answer #3 · answered by cdb g 1 · 0⤊ 0⤋
checked and all balanced
2006-12-17 10:59:09 · answer #4 · answered by mr man 2 · 0⤊ 0⤋
they are balanced....
no more work required
2006-12-17 10:44:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋