A sample of gas has a volume of 5.00L at 27oC. Assuming constant pressure, at what temperature will the volume become doubled?
a. 54 degrees C
b. 177 degrees C
c. 273 degrees C
d. 327 degrees C
e. 600 degrees C
2006-12-17 10:13:22 · 6 answers · asked by bosox1989 1 in Science & Mathematics ➔ Chemistry
I think the temp has to be in Kelvin not degrees, so you have to add 273 to the degrees c to get the initial temp to work with.
so you get T1 = 27 + 273 = 300K
T2 = 300 x (10/5) = 600K
which is (600-273) degrees C,
327 degrees C
2006-12-17 10:24:32 · answer #1 · answered by the_moose 1 · 0⤊ 0⤋
V1/T1 = V2 /T2
5*(27+273)=10*x
x=150 degrees K
2006-12-17 10:52:42 · answer #2 · answered by mr man 2 · 0⤊ 0⤋
27 oC is 300 K. To double the volume at constant pressure we must double the absolute temperature. So the temperature is 600 K or 327 oC.
The right answer is (d).
2006-12-17 10:26:07 · answer #3 · answered by Dimos F 4 · 0⤊ 0⤋
327 C
2006-12-17 10:17:12 · answer #4 · answered by Sergio__ 7 · 0⤊ 0⤋
a. 54 degrees C
i believe this is gay-lussacs(No-name) law, V1/T1=V2/T2
so its just a proportion (5.00/27)=(10.00/x) and just solve for x
2006-12-17 10:19:04 · answer #5 · answered by Rizwan P 1 · 0⤊ 1⤋
Universal Gas Law:
(P1/V1)/T1 = (P2/V2)/T2
Simple algebra...
(P1/5L)/300K = (P2/V2)/300k
If P1 = P2 you can just make it 1 or any number you like!
you do the math!
2006-12-17 10:25:23 · answer #6 · answered by Anonymous · 0⤊ 1⤋