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Hello,

How can I find the solution for this equation:

sqrt(x) = 1+a/x

if this equation has a name, whats is it called??

Thanks in advance for your help.

2006-12-17 09:36:58 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

square both sides:
x = (1+a/x)^2
x = 1 +2a/x + a^2/x2
finding the common denominator:
x = x^2/x^2 +2ax/x^2 + a^2/x2
multiplying both sides by x^2
x^3 = x^2 + 2ax + a^2
The right side is a perfect square:
x^3 = (x+a)^2

I hope this helps

2006-12-17 11:33:50 · answer #1 · answered by Renaud 3 · 0 0

√x = 1 + a/x

Square both sides.
x = (1 + a/x)^2 = 1 + 2a/x + a^2/x^2

x - 1 - 2a/x - a^2/x^2 = 0
x^3 - x^2 - 2ax + a^2 = 0

Now it looks like a cubic equation.

2006-12-17 17:46:32 · answer #2 · answered by Northstar 7 · 0 0

Simplify:
(\/x)² = (1+a/x)²
x = [1² + 2a/x + (a/x)²]
::

2006-12-17 17:39:40 · answer #3 · answered by aeiou 7 · 0 0

Are you sure you copied the problem correctly? We can only solve for one variable, either "x" or a..."

2006-12-17 18:12:21 · answer #4 · answered by ♪♥Annie♥♪ 6 · 0 0

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