b^2 -40 = -15
add 40 to both sides
b^2 - 40 + 40 = -15 + 40
b^2 = 25
b=sqrt(25)
b=5 or -5
2006-12-17 09:26:07
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answer #1
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answered by bkc99xx 6
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b² - 40 = -15
+ 40 + 40
b² = 25
b = +5, -5
2006-12-17 17:28:32
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answer #2
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answered by anthonycs5 1
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b^2 - 40 = -15
First: our goal is solving for "b," and let's make sure "b" is on the left side: add 40 to both sides:
b^2 - 40 + 40 = -15 + 40
b^2 = 25
Second: get rid of the exponent by finding the square root of both sides:
b = +/- the square root of 25
b = -5, 5
2006-12-17 18:45:07
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answer #3
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answered by ♪♥Annie♥♪ 6
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Like this:
b squared - 40= -15
b squared -40 +40= -15+40
b squared equals 25
2006-12-17 17:28:42
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answer #4
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answered by OZZY 1
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Add 40 to both sides.
b squared - 40 + 40 = -15 + 40
b squared = 25
then take the square root of both sides.
b = +/- 5
since both (-5) squared and (5) squared are 25.
2006-12-17 17:28:06
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answer #5
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answered by kwoogief 2
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b^2 - 40 = -15
add 40 to each side and get b^2 = 25
Take the square root of each side and get b = +/- 5
Try and get a handle on this stuff to understand it. Otherwise anyone could give you any bs answer and you wouldn't know if it's right or wrong, or why. Also you need to be albe to do it on your own for the test and that means you need to understand it.
2006-12-17 17:27:28
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answer #6
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answered by Joni DaNerd 6
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b^2-40=-15
b^2 -40 +40 = -15 + 40
b^2 = 25
sr 25 = 5
b= 5
2006-12-17 17:27:26
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answer #7
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answered by lynn c 2
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b^2 - 40 = -15
Add 40 to each side
b^2 - 40 + 40 = 40 - 15
b^2 = 25
b = 5 (actually +5 or -5, how picky is your instructor?)
2006-12-17 17:26:40
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answer #8
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answered by Steve A 7
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1) add 40 to each side
b^2 = 25
2) take the square root of both sides :
b = negative or positive 5
good luck
2006-12-17 17:26:49
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answer #9
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answered by Gardenia 6
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b squared=40-15
b squared=25
b= square root of 25
b is either 5 or -5
This is basic stuff. You really need to be able to do this on your own.
2006-12-17 17:28:10
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answer #10
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answered by jon_k1976 3
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