2006-12-17 09:11:27 · 9 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
First: find the greatest common factor > by finding a number that's divisible by 36 and -4. We can use: 4
Second: take 4 and bring it the front and multiply it by the remaining variables:
= 4(9x^2 - y^2)
Third: factor the expression in the parenthesis: (3x - y)(3x+y) and rewrite:
= 4(3x - y)(3x+y)
2006-12-17 11:35:41 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
1) 36 is 6^2, x^2 is x * x , 4 is 2^2 , and Y^2 is y *y
2) so (6x-2y)(6x+2y) is a simple form of 36x^2 - 4y^2
3) to make it more simple : you can multiply each part by 1/2
and you'll get 4(3x-y)(3x + y)
2006-12-17 09:20:59 · answer #2 · answered by Gardenia 6 · 1⤊ 0⤋
the way your wrote this out doesn't rather make experience... yet when for the first element you attempt to element -4y^2+12y-16 Then the answer should be -4(y-4)(y+a million) And if the 2d crew of stuff is all meant to be for the issue 42x^3y^4-63x^2y then you actually could get -21xy^3
2016-11-27 00:44:37 · answer #3 · answered by ? 3 · 0⤊ 0⤋
4(3x-y)(3x+y)
take the GCF out (4) which gives you 4(9x^2-y^2)
then factor by difference of sq.
to give you 4(3x-y)(3x+y)
2006-12-17 09:15:13 · answer #4 · answered by k soni 2 · 0⤊ 0⤋
36x^2 - 4y^2
4(9x^2-y^2)
4(3x+1)(3x-1)
2006-12-17 09:13:34 · answer #5 · answered by yupchagee 7 · 0⤊ 2⤋
= 4(9x^2 - y^2) = 4(3x-y)(3x+y)
2006-12-17 09:14:35 · answer #6 · answered by kellenraid 6 · 0⤊ 0⤋
diff of squares:
(6x - 2y)(6x + 2y)
Can also factor out 2 from both:
4(3x - y)(3x + y)
2006-12-17 09:13:15 · answer #7 · answered by Jim Burnell 6 · 1⤊ 0⤋
4(9x^2-y^2)
4(3x-y)(3x+y)
2006-12-17 09:14:56 · answer #8 · answered by abcde12345 4 · 0⤊ 0⤋
4(3x-y)(3x+y)
2006-12-17 09:18:22 · answer #9 · answered by imamulleith 2 · 0⤊ 0⤋