a. Write a molecular equation for the reaction.
b. Which of the possible products is the precipitate, and how do you know?
c. Write a complete ionic equation for the reaction and identify the spectator ions in the equation.
d. Write a net ionic equation for the reaction between lead(II) nitrate and potassium iodine.
2006-12-17 08:46:34 · 2 answers · asked by kittyvamptress 2 in Science & Mathematics ➔ Chemistry
(a) Pb(NO3)2(aq) + 2 KI(aq) --> PbI2(s) + 2 KNO3(aq)
(b) PbI2 will precipitate because lead salts, particular lead halides, are insoluble
(d) Pb2+(aq) + 2 I-(aq) --> PbI2(s)
You can figure out the spectator ions and the complete ionic equation from the first and the last ones...
2006-12-17 09:08:47 · answer #1 · answered by hcbiochem 7 · 1⤊ 0⤋
Start at the end: Pb2+(aq) + 2I-(aq) ----> PbI2(s)
You will see a brilliant yellow precipitate.
Now you can work backwards, and fill in the rest.
2006-12-17 17:05:44 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋