How do i solve this problem?

Question

Roy says he has more nickels than dimes. id he has 5.20, how many of each coin does he have?

Answer 1

Well, there's LOTS of solutions, but they all have more nickels in them than when X nickels + X dimes = 5.20

10x + 5x = 520
15x = 520
x < 35 (like 34.666)

So, if there's 35 dimes and 34 nickels, you get 5.20, simply replace X dimes and put in 2X nickels, and you'll have your solutions for each value of 1 <= X <= 35

Answer 2

He can have one dime and 100 nickeles. $5.20/5 = 102 nickles.
If all of the money were dimes. Then, he'd have 52 dimes. If all of it was nickles. Then he'd have 102 nickles. If dimes were divided by two 52/2=26. There would be 26 dimes on each side. But,if half were nckles.Then 26 * 2 = 52 nickles. The rest 26 would be dimes.

Answer 3

vague question
how about 0 dimes?
why not 5 $1 bills and 4 nickels?
or all nickels? 104 nickels?

if you need some specific relationship, like say 1 more nickel than dime, something like:

.10 * x + .05*(x+1) = 5.20

x = # dimes, x+1=# nickels

or whatever the problem calls for