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[1/t+1] - [1/t-1]

2006-12-17 08:18:28 · 2 answers · asked by highrllr0079 2 in Science & Mathematics Mathematics

2 answers

Assuming you didn't miss some parentheses (I bet you did....):

1/t + 1 - (1/t - 1) =
1/t + 1 - 1/t + 1 = 1 + 1 = 2

2006-12-17 08:21:06 · answer #1 · answered by Jim Burnell 6 · 0 0

AS in arithmetic, you need to get the fractions with the same common denominator. It is (t+1)(t-1)

Multiply numerator and denominator of each fraction by the factor needed.

(t-1)/(t+1)(t-1) - (t+1)/((t-1)(t+1)

now write it as a single fraction adn keep the numerators in the parentheses

[(t-1)-(t+1)]/(t+1)(t-1)

simplify the numerator by removing ( ) and combining like terms

(t-1-t-1)/(t+1)(t-1)
-2/(t+1)(t-1)

this is as far as you can simplify because there are no common factors.

2006-12-17 16:25:40 · answer #2 · answered by mom 7 · 0 0

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