How many g of CCl4 can be formed from 2.6 g of Cl2 in this reaction? CH4 + 4Cl2 -> CCl + 4HCl?

Answer 1

Cl2 has a molar mass of 71
So moles = mass / molar mass = 2.6 / 71 = 0.0366 moles

From the stoichiometry, 4 mol of Cl2 give 1 mol of CCl4
0.0366 moles of Cl2 give ?

0.0366 * 1 / 4 = 0.009155 mol of CCl4

Mass = no of mol * molar mass (154 for CCl4)
= 0.009155 * 154 = 1.41g

Answer 2

Your balanced equation should be:

CH4 + 4Cl2 = CCl4 + 4HCl

Get the molecular mass of Cl2 (look up Cl on the periodic chart and multiply by 2). Write this above the Cl2 in the balanced equation.

Get the molecular mass of CCl4 (add up the atomic masses from the periodic chart). Put this number above the CCl4 in the equation.

In the balanced equation the ratio between Cl2 and CCl4 is 4:1 so multiply the chlorine number by 4 and put this underneath the Cl2 in the balanced equation. Put the CCl4 number below the CCl4 in the balanced equation. You now have the gram ratio between the two - use it to convert grams of Cl2 to grams of CCl4:

grams CCl4 = grams Cl2 x grams CCl4/grams Cl2.

Round off your answer to two sig. figs.