write the equation in standard form using INTEGERS.
1) y=2/3x+7
2) y=5/3x-11
2006-12-17 07:31:16 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1) y=2/3x+7
assuming you mean:
y= 2x/3 +7
3y=2x + 21
2x-3y + 21 =0
2) y=5/3x-11
again, assuming you mean: y= 5x/3 -11
3y=5x -33
5x-3y-33=0 .
2006-12-18 13:50:33 · answer #1 · answered by Anonymous · 2⤊ 0⤋
If you need to use integers you have to eliminate the fractions. Since the denominator of the fraction is a 3, multiply all of your terms by 3 (that gets rid of the fraction) and rearrange into standard form.
1: multiply by 3 then rearrange
3y= 2x +21 becomes 2x-3y = -21 using standard form
2: multiply by 3 then rearrange
3y = 5x -33 becomes 5x-3y = 33
2006-12-17 15:35:59 · answer #2 · answered by The Old Professor 5 · 0⤊ 0⤋
1) y= 2x/3 +7
3y=2x + 21
2x-3y + 21 =0
2) y= 5x/3 -11
3y=5x -33
5x-3y-33=0
2006-12-20 11:02:11 · answer #3 · answered by pedazodegente 1 · 0⤊ 0⤋