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okay,
1. write out the chemical equation in words for each of the reaction which gave you precipitate:
( in the lab, I got this equations that gave me ppt)
- HgCl2{Mercury II Chloride} w/ No2(Co3) {Sodium Carbonate}
- No2(Co3) {Sodium Carbonate} w/ Pb(No3)2 {Lead II nitrate)
- No2(Co3) {Sodium Carbonate} w/ KI {Potassium iodide}
- Pb(No3)2 {Lead II nitrate) w/ Na2(SO4){Sodium Sulfate)
-BaCl2 {Barium Cloride} w/ Na2(SO4){Sodium Sulfate)
-CuCl2 {Copper II chloride} w/ No2(Co3) {Sodium Carbonate}
- CuCl2 {Copper II chloride} w/ KI {Potassium iodide}

there are a lot more, but those are that I dont understand

also what are chemical "word" and how do I write the corresponding chemical equations using the correct chemical for each below chemical "word"?

one last thing, what are cloudy precipitate?

2006-12-17 07:20:17 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

dude you can teach better than my science teacher
you make sense

But just one question, how come u put the two on front of the solution on the equation part?
how did u get the two there

2006-12-17 10:22:00 · update #1

2 answers

The names of your reactants have two words. Switch the first word in each name to get the name of the two new products.

If you have to identify which of the new substances formed the precipitate, look for a compound that does not contain sodium or potassium (I don't see anything in your third equation that would form a precipitate).

When a new substance forms that is "insoluble" in water, that means it "falls" out of solution as a precipitate and the solution looks cloudy. That's how you recognize the formation of a precipitate - the solution turns cloudy.

I'll do the first reaction for you:

Mercury(II)chloride plus sodium carbonate form sodium chloride and mercury(II) carbonate (the precipitate).

If you need the equation using formulas you would write:

HgCl2 + Na2CO3 = 2NaCl + HgCO3(s) [the (s) indicates the precipitate)

2006-12-17 07:33:18 · answer #1 · answered by The Old Professor 5 · 0 0

A chemical equation can continuously be balanced no matter if that is a precipitation reaction or no longer. If there isn't any precipitate at the same time as 2 ideas are mixed, there isn't any reaction in any respect. A precipitate is a fabricated from a reaction at the same time as 2 ideas are mixed. A precipitate is a sturdy formed because 2 soluble aqueous chemical substances react to style an insoluble sturdy contained in the answer.

2016-11-27 00:36:17 · answer #2 · answered by oroza 4 · 0 0

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