English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

please i need help before i fail my test tomorrow in math!!

2006-12-17 06:48:01 · 2 answers · asked by RyBialach 1 in Education & Reference Homework Help

2 answers

ok, basically in the real number system, you can't have the square root of a negative number. Like, what can you multiply by itself to get, for example, -4? You can't. 2 x 2 = 4. and -2 x -2 = 4.

So some person said, let's make up imaginary numbers that, when you square them, become negative. That is the number i. i = squareroot of -1, or more simply, i^2 = -1.

If you gave me an example of a problem, I could explain how i works. My email is teekshi33@yahoo.com.

Hope that helps!

2006-12-17 06:54:54 · answer #1 · answered by teekshi33 4 · 1 0

the first poster stated it pretty well (clap clap clap)!

here's a link to how the imaginary "i" is extended to complex numbers:

http://www.clarku.edu/~djoyce/complex/numberi.html

2006-12-17 15:14:09 · answer #2 · answered by gggjoob 5 · 0 0

fedest.com, questions and answers