sec^2 + tan^2 = 1 is an identity?

Question

True or false

Answer 1

Well we have

sin^2(x)+cos^2(x)=1

Then divide the above identity by cos^2(x)

sin^2(x)/cos^2(x)+cos^2(x)/cos^2(x)=1/cos^2(x)

tan^2(x)+1=sec^2(x)

Since
tan^2(x)=sin^2(x)/cos^2(x)
and
sec^2(x)=1/cos^2(x)
:)

Answer 2

False: its 1+tan 2 = sec 2

Answer 3

false
its
( -sec^2+ tan^2 = 1 )

Answer 4

False
1 + tan² u = sec² u
is the correct identity. It follows from
sin² u + cos² u = 1
when you divide throughout by cos² u.

Answer 5

false

1 + tan^2(x) = sec^2(x) is an identity

Answer 6

This is false. It should read sec²x -tan²x = 1.
In other words, the + sign should be a - sign.

Answer 7

false

Tan^2+1=Sec^2
1=Sec^2-Tan^2

Answer 8

false
sec^rx-tan^2x=1