LCM Problem?

Question

(2/g + g/h) / 2/h

Answer 1

I assume you're trying to simplify this?

For the numerator, the LCD is just gh so:

2/g * gh/gh + g/h * gh/gh
2h/gh + g^2/gh = (g^2 + 2h)/gh

Then you can change the problem to a multiplication problem by flipping the denominator:

((g^2 + 2h)/gh) / 2/h
(g^2 + 2h)/gh * h/2 = (g^2 + 2h)/2g

Answer 2

=[2h+g^2]/gh*h/2
=[2h+g^2]/2g

Answer 3

[(2h+g^2)/gh]*h/2
=(2h+g^2)*h/2gh
=(2h+g^2)/2g