Remember that the range is the possible answers you can get for y, given that x is restricted to being between -5 and 5.
Since 1/x goes to negative infinity as x approaches zero from the left, and positive infinity as x approaches zero from the right, the range is:
(-inf, -1/5] U [1/5, inf)
Another way to write this would be:
"All real numbers EXCEPT numbers between -1/5 and 1/5."
To see this, pick a number really close to zero, and check it on both sides:
y = 1/(1/100,000) = 100,000
y = 1/(-1/100,000) = -100,000
2006-12-17 04:16:27
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answer #1
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answered by Jim Burnell 6
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the curve never touches the y
or the x axes,so the range is
plus or minus infinity including
-1/5 and 1/5,but excluding all
real numbers greater than
-1/5 and less than 1/5
range:
[-infinity,-1/5] U [1/5,+infinity]
i hope that this helps,since
x approaching plus or minus
zero is in the domain -5 to
+5
2006-12-17 06:10:03
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answer #2
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answered by Anonymous
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-1/5 <= y < 0 and 0 < y <= 1/5 should be your range.
2006-12-17 04:16:15
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answer #3
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answered by Anonymous
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You have to sub in -5, -4 etc. for x.
This is because x = domain and y = range.
So, to figure out the first one.
y = 1/-5
y = .2
.2 will be the first value for the range, corresponding to -5 on the domain.
next:
y = 1/-4
and so on.
2006-12-17 04:18:41
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answer #4
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answered by Yanni 1
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y= 0.2 to 5
2006-12-17 04:16:52
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answer #5
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answered by Anonymous
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