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5 answers

Remember that the range is the possible answers you can get for y, given that x is restricted to being between -5 and 5.

Since 1/x goes to negative infinity as x approaches zero from the left, and positive infinity as x approaches zero from the right, the range is:

(-inf, -1/5] U [1/5, inf)

Another way to write this would be:

"All real numbers EXCEPT numbers between -1/5 and 1/5."

To see this, pick a number really close to zero, and check it on both sides:

y = 1/(1/100,000) = 100,000
y = 1/(-1/100,000) = -100,000

2006-12-17 04:16:27 · answer #1 · answered by Jim Burnell 6 · 1 0

the curve never touches the y
or the x axes,so the range is
plus or minus infinity including
-1/5 and 1/5,but excluding all
real numbers greater than
-1/5 and less than 1/5

range:
[-infinity,-1/5] U [1/5,+infinity]

i hope that this helps,since
x approaching plus or minus
zero is in the domain -5 to
+5

2006-12-17 06:10:03 · answer #2 · answered by Anonymous · 0 0

-1/5 <= y < 0 and 0 < y <= 1/5 should be your range.

2006-12-17 04:16:15 · answer #3 · answered by Anonymous · 0 1

You have to sub in -5, -4 etc. for x.

This is because x = domain and y = range.

So, to figure out the first one.

y = 1/-5
y = .2

.2 will be the first value for the range, corresponding to -5 on the domain.

next:

y = 1/-4

and so on.

2006-12-17 04:18:41 · answer #4 · answered by Yanni 1 · 0 1

y= 0.2 to 5

2006-12-17 04:16:52 · answer #5 · answered by Anonymous · 0 1

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