y over y - 4 = 5 + 2 over y - 4
2006-12-17 03:23:46 · 5 answers · asked by JUAN CARLOS R 1 in Science & Mathematics ➔ Mathematics
First multiply both sides by y-4 to get:
y=5+2 so y=7
2006-12-17 03:30:50 · answer #1 · answered by knock knock 3 · 1⤊ 0⤋
y/(y - 4) = 5 + 2/(y - 4)
Your first step is to eliminate ALL fractions. This is done by multiplying both sides by (y - 4). This would eliminate the (y - 4) denominators, and it will be multiplied onto the 5.
y = 5(y - 4) + 2
At this point, it becomes simple algebra.
y = 5y - 20 + 2
18 = 4y
y = 18/4 = 9/2
By the way, your question is ambiguous. Do you mean
5 + 2/y - 4, or
5 + 2/(y - 4)?
Brackets make a huge difference.
2006-12-17 11:33:37 · answer #2 · answered by Puggy 7 · 0⤊ 1⤋
(y/y - 4) = (5+2/y - 4)
First: get rid of fractions by taking the denominators and multiplying them by everything on both sides:
(y - 4)(y/y - 4) = (y - 4)(5+2/y - 4)
Second: cross cancel like terms on both sides: cancel y - 4 on both sides and solve:
y = 5+2
y = 7
Third: *check the problem by taking 7 and replacing it with the variable "y."
7/7 - 4 = 5+2/7 - 4
7/3 = 7/3
2006-12-17 12:38:40 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Multiply through by y-4 each of the terms.
You get y = 5(y-4) + 2
Distribute
y= 5y-20+2
y=5y-18
Subtract 5y from both sides
-4y = -18
Divide by -4 so y=-18/-4=18/4=9/2=4.5
Check:
4.5/(4.5-4) = 5 + 2/(4.5-4) ?
4.5/.5 = 5+ 2/.5 ?
9 = 5 + 4 Yes
2006-12-17 11:33:03 · answer #4 · answered by Professor Maddie 4 · 0⤊ 1⤋
What knock knock said is the answer- quick, simple
2006-12-17 12:34:58 · answer #5 · answered by Anonymous · 0⤊ 1⤋