xsq - 5x = 3 solve for x?

Answer 1

There is no solution!
only imaginary numbers can work out.. but you can also say there is no solution in real numbers

see
if y = xsq-5x-3

and then x cannot be negative number. so starting with 0, y = -3

and, xsq woould always be less than 5x

and y would always be negative


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OOPS.. i thougt sq means square root!!

lol

Answer 2

x^2 - 5x = 3

First: set the equation to equal zero:

x^2 - 5x - 3 = 3 - 3
x^2 - 5x - 3 = 0

Second: factor, if possible. In this case, we can't factor. Then, use the quadratic formula. Take your coefficients:
a = 1, b = -5, c = -3 and place them in the quadractic formula: you should get:

x = -(-5) +/- the sq root of [(-5)^2-4(1)(-3)]/2(1)

x = 5 +/- the sq root of [25 - 4(-3)/2]

x = 5 +/- the sq root of [25 +12/2]

x = 5 +/- the sq root of 37/2

x = 5 + the sq root of 37/2 and 5 - the sq root of 37/2

Answer 3

Set to zero and factor if you can:

x^2-5x-3=0

Since it does not factor, you need the quadratic formula:

x=( 5 +/- sqrt( 25-4*1*(-3)) ) / 2

x= (5 + sqrt (37)) / 2 or (5 - sqrt (37)) / 2

Answer 4

x² - 5x = 3
x² - 5x - 3 = 0
x = {5±√(25-4(-3))}/2
x = 2.5±0.5√37
x = 5.5414 or x = -0.5414

Answer 5

x^2 - 5x - 3 = 0
D= 25 + 4*3 = 37

x= (5+/-root37)/2

x=5.541 and x=-0.541

Answer 6

x^2-5x-3=0
x=[5+/-rt(25+12)]/2
x=5/2+/-rt37/2

Answer 7

x = 3/(sq-5)