Suppose that a line of 1km is drawn at an angle of 1 degree. Suppose that a perpendicular is drawn from the end point of the 1km line to the centre line(180 degrees), what would be the length. Also let me know the procedure to find this.
2006-12-17 02:44:03 · 3 answers · asked by amir 1 in Science & Mathematics ➔ Mathematics
Still a little hard to follow but I think I got you. Still not sure if you're referring to the lenth along the x axis (centre line?) or if you're referring to the lengthof the perpendicular, so I'll tell you how to get both. Here's how you do it;
Suppose (x,y) is the endpoint of the line. Then the center line (180 degrees, I suppose you mean the x axis) would have coordinates (1 km cos 1 degree, 0) at the point directly beneath the endpoint of your line, where the perpendicular would meet it. So the projection along the x axis would be 1 km * cos 1 degree which is .998 km.
However, the length of the perpenducular would be 1 km * sin 1 degree , as above.
You need to understand that trig functions are set ratios that occur within right triangles on the Euclidean (flat) plane, they don't depend on the size or orientation of th etriangles. When you understand this you will know which trig function to use, and how, and why.
2006-12-17 03:06:41 · answer #1 · answered by Joni DaNerd 6 · 0⤊ 0⤋
the question's little confusing..but think i have got it..
it's just a trigonometric problem:
it's length =
1 km x sin 1
0.0175 km
or = 17.45 m
2006-12-17 10:48:06 · answer #2 · answered by no man 2 · 0⤊ 0⤋
you will find it in "millons of question in mind"its a book by G.R. PATEL
2006-12-17 10:53:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋