2006-12-17 00:16:23 · 7 answers · asked by manoj g 1 in Science & Mathematics ➔ Earth Sciences & Geology
ok you cah get to kind of speed one is linear speed and the other is momentom speed
for linear speed use the aqution c=(2*3.14*dectans between eart&sun) / (365.25*24*3600) m/s
and for momentom speed use:
linear speed = momentom speed * dectance between earth&sun
or
momentom = ( 2*3.14) / (365.25*24*3600) radyan/sec
2006-12-17 00:31:22 · answer #1 · answered by mms 3 · 0⤊ 0⤋
Multiply 92,900,000 by 3.1415926. This will give you the distance of one earth orbit around the sun in miles. Divide that by 365 and this will be the distance travelled in one day. Divide that by 24 and that will be the distance in one hour.
2006-12-17 08:41:53 · answer #2 · answered by kevpet2005 5 · 0⤊ 0⤋
Max. orbital speed - 30.287 km/s (109,033 km/h)
Average orbital speed - 29.783 km/s (107,218 km/h)
Min. orbital speed 29.291 km/s (105,448 km/h)
2006-12-17 09:49:17 · answer #3 · answered by Anonymous · 0⤊ 0⤋
ITS NEARLY 30 KMPHR THE EXACT VALUE IS 30.278
2006-12-21 07:07:01 · answer #4 · answered by bosco 2 · 0⤊ 0⤋
about 30 kilometers per second...
2006-12-17 10:00:37 · answer #5 · answered by ashwin_hariharan 3 · 0⤊ 0⤋
1 day / year!!!! ha ha ha
2006-12-17 08:33:05 · answer #6 · answered by raindrops 5 · 0⤊ 0⤋
30.287 km/s
(109,033 km/h)
2006-12-17 09:23:12 · answer #7 · answered by James Chan 4 · 0⤊ 0⤋