Proof 1 = 0
1^1 = 1
1^0 = 1
1^1 = 1^0
bases are equal so powers are equal
1 = 0
I can't be sure if i remembered it rigth.
2006-12-16 23:19:35
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answer #1
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answered by ray2_moot 2
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About which topic or subject?
For every field, there are its own tricks.
I'll give you tricks on algebraic manipulations.
1) Add and subtract the same number.
Ex. Express the polynomial x^2-5x+7 in terms of a polynomial in the expression (x-10).
Ans. replace x with (x-10)+10 to get:
[(x-10)+10]^2 -5[(x-10)+10] +7 =
(x-10)^2 + 20(x-10) +100 -5(x-10) -50+7 =
(x-10)^2 + 15(x-10) +57
2) Especially in multiple choice questions, try the answers if applicable. You sometimes do not need to carry out a lengthy procedure while you have the possible answers in front of you. Just try them. This may prove very helpful in exams if you want to solve an equation or make a statement of truth about a question asking about the validity of an identity. Just try the possible numbers for the equation and pick up numbers of your own for an identity to check it.
Ex. if (49^x + 49^-x) = 7, what is (7^x + 7^-x)?
Ans. Just try choices.
2006-12-17 07:25:53
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answer #2
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answered by mulla sadra 3
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Create a set of cards, numbers on them are in sequence.
One card has numbers 1 3 5 7 9 11 13 and so on up to 63 (all odd numbers; write one, skip one)
One card has numbers 2 3 6 7 10 11 14 15and so on up to 63 (write two, skip two)
One card has 4 5 6 7, 12 13 14 15, 20 21 22 23 and so on up to 63 (write four, skip four)
One card has 8 9 10 11 12 13 14 15, 24 25 26 27 28 29 30 31, and so on up to 63 (write eight, skip eight)
One card has 16 17 [...] 30 31, 48 49 [...] 63 (write sixteen, skip sixteen)
One card has 32 33 [...] 62 63 (write thirty two)
Let someone think of a number, between 1 and 63 inclusive. Shuffle the cards.
For each card:
Is the number on this card?
If the answer is yes, add up the number on the upper left hand side (1,2,4,8,16,32). If the answer is no, skip that number.
The resulting number is the answer, unless that other person lied.
2006-12-17 09:37:17
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answer #3
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answered by Anonymous
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You can find square of two digit number ending in 5 such as 15 ^2, 25 ^2 etc up to 95 ^2 mentally.15^2 is 225. This way you can get it.
Add one to the number in tens place. In this case it is 1+1=2. Multiply by this sum(2) with the number in tens place(1). You get 2*1=2. By the side of this product(2)write 25. Then you get the final answer as 225.
Try 85^2.Adding one to 8 we get 9. Multiplying 9 and 8 we get 72. So answer is 7225.Now ask what is 65 ^2s? Answer is 4225.What is 0.75 ^2? Simple. First find 75^2 which is 5625.Place decimal point.Get:0.5625
2006-12-21 00:39:46
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answer #4
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answered by madhu 2
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Just Think of one number. multiply it with 2. Add 6. Multiply 3. multiply with 5. then multiply with 3. add 6. Add the digits of your answer until it becomes single digit number. Example - if the answer is 124 then 1+2+4 = 7 if it is 89 then 8 + 9 = 17 = 1+7 = 8. OK. Your answer is 6.
2006-12-21 07:22:13
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answer #5
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answered by vichitra 2
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Multiply 9 by any number. The answer will always add up to 9. eg 9x111=999. 9+9+9=27. 2+7=9.
Weird huh?
2006-12-17 08:46:15
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answer #6
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answered by kevpet2005 5
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1/ New ‘rule’ with ratios.
Write 60 over 10, delete 0s, result is 6; correct? Write 95 over 19, now delete both 9s, result is 5, Correct! They would not believe you. Don’t let them doing their own examples and tell Why not? 64 over 16, now delete both 6s, result is 4!; 65/26 = 5/2 Check it!! Find more examples.
2\ put-up a number and don’t tell me, add it to itself, add 10, multiply by 3, subtract 30, divided by put-up number, subtract 4, result is 2, isn’t it?
3/ draw and “explain” what you are doing. I draw a circle with R=10 and center point A; I draw both x and y diameters; now I draw a rectangle ABCD, (point C being on the circle); I draw the diagonal BD (DON’T draw AC); now tell them AB=3.14 and AD=8.96 find BD!
Now stop talking and see what they would do. Pythagorean? Do you see why BD=10=R?
2006-12-17 10:18:35
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answer #7
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answered by Anonymous
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well,u didnt specify the topic but let me tell u one..
i m going to tell u abt getting squares for nos tht end with 5..
for eg,
25 x 25 = (2 x next no)(5 x 5)
=(2 x 3)(5 x 5)
= 625
similarly,
35 x 35 = 1225
45 x 45 = 2025
55 x 55 = 3025
and so on.........
2006-12-17 07:52:50
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answer #8
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answered by For peace 3
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Hi! this is shama. do you know how to multiply numbers that are in the scientific notation? instead of turning the numbers into standard notation, this is what you could do.
3.52* 10*10*10*10(ten to the 4th power) times 1.4 *10*10(ten to the second power
multiply 3.52 times 1.4 and multiply 10 to the 4th power and 10 to the second power together and you get 4.928 * 10 to the 6th power.
this is much easier than multiplying all the zeros together!
2006-12-20 16:32:45
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answer #9
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answered by chotishama 2
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Try bokks of Vedic Maths, Speed Maths + Shakuntala Devi's series......
2006-12-17 23:37:44
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answer #10
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answered by raghunandan r 1
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