Please help me in field of Chemical Euqilibrium...?

Question

My question is this:

There is a euqilibrium system, containing N2,H2 and NH3. The equation of the system is:

N2(g) + 3H2(g) <=> 2NH3(g)

If we add an amount of Argon (Ar, Z=36) gas to the system, What will happen on the euqilibrium, and amount of the N2,H2 and NH3? Does Euqilibrium System changed?

(Notice that the amount of the Argon gas is not so much to reduce the system's volume in a notable size.)

Answer 1

Since the amount of the Argon gas is not so much to reduce the system's volume in a notable size, the PARTIAL PRESSURES of the reactants and the product is also affected in a small way.

Moreover Argon is inert.

Due to change in partial pressure , only the equlibrium constant is affected. Thus the time of attainment of chemical equilibrium is affected and the POSITION OF CHEMICAL EQUILIBRIUM remains UNAFFECTED.

The amount of N2, H2, NH3 remains the same as it was before addition of argon.

Answer 2

N2(g) + 3H2(g) <=> 2NH3(g)

if you add an amount of Argon, more NH3 will be produce. Because the Chemical Euqilibrium will move to way such that reduce the number of atoms of gas

Answer 3

The equilibrium will shift to the right to reduce the volume increased.

Hence, amount of N2 and H2 decrease and volume of NH3 increase.

(How is Argon goin to reduce the system's volume, it will increase since it has volume)

Answer 4

The equilibrium has not changed, but the pressure of the system may change at constant volume, depending on the amount of argon gas added.

Answer 5

on addition of argon:

argon is an inert gas for the given equilibrium as it does not take part in the reaction.Now,it is added at CONSTANT VOLUME to the reaction mixture at equilibrium therefore there will be no change in the state of equilibrium as the molar concentrations
of the reactants and product does not change

amount of N2,H2,NH3 remain same

Answer 6

no change, u can think of this as addition of argon on both sides of the equation.there is no change in the relative pressure.so no change in the equilibrium position.
cheers