2006-12-16 19:05:55 · 7 answers · asked by hancee banana 1 in Education & Reference ➔ Standards & Testing
You're getting a lot of BS answers from *******. Here's the real breakdown:
IQ_________Description______% of Population
130+_____Very superior_____2.2%
120-129___Superior________6.7%
110-119___High average____16.1%
90-109____Average________50%
80-89_____Low average____16.1%
70-79_____Borderline______6.7%
Below 70__Extremely low___2.2%
So 117 is high average, almost superior
2006-12-16 20:30:50 · answer #1 · answered by ZenPenguin 7 · 3⤊ 0⤋
Big enough to hopefully keep you out of trouble in life. Now use that IQ to study hard and you will increase it dramatically. Never stop learning and the sky is the limit on what your IQ will one day be.
2006-12-17 04:19:05 · answer #2 · answered by grandknca 2 · 0⤊ 0⤋
It depends on the test taken. On one test, it might be in the 80th percentile, on another it might only be something like 60th percentile.
If you're trying to find out your IQ from online tests, they are very unreliable, not to mention you don't actually have a means of determining the percentile. While they can be fun to do, they don't provide any meaningful information. I've had results varying from 125 all the way to 178!
Here: http://www.mensa.org.uk/iq-levels/ Check out the section on Comparison of Tests.
2006-12-17 01:17:39 · answer #3 · answered by glurpy 7 · 0⤊ 0⤋
100 iq is average.... so 117 is above average....
2006-12-16 19:14:31 · answer #4 · answered by Meh... 3 · 1⤊ 0⤋
117 is pretty "average".
2006-12-16 19:15:01 · answer #5 · answered by googleplex 6 · 0⤊ 0⤋
80-120 low
121-140 average
141-160 smart
161+ Geniuss
I scored somewhere above 160 but I was 11 and the test was designed for adults so I guess I have about 200+. But if my teachers ever found out they would make me do more homework and skip grades and put me in gifted classes and stuff.
2006-12-16 19:17:02 · answer #6 · answered by darrkadlubowski 3 · 0⤊ 5⤋
average to low range. 160 is genius.
2006-12-16 19:13:30 · answer #7 · answered by Patrick 2 · 0⤊ 1⤋