another one..ty!?

Question

age problems..
show the representation,equation,solution and final answer..
thank you!

Richard is twice as old as Alvin. The sum of their ages is 36 years old. Find their present ages.

Answer 1

The first thing we do is assign a variable to the standard of comparison. In this case, since Richard is described to be twice as old as Alvin, you would assign x to be Alvin, so Alvin would be the standard of comparison.

Let x = Alvin's age. Then, since Richard is twice as old as Alvin,
2x = Richard's age.

We know that the sum of their ages is 36; therefore,

x + 2x = 36

Now, this is simple algebra.
3x = 36
x = 12

Since x represents the age of Alvin, Alvin is 12 years old.
Richard is twice as old as Alvin, so Richard is 2(12) = 24 years old.

Answer 2

Richard is twice as old as Alvin.So Richard is 2x and Alvin is 1x.
1+2=3
Take the total sum of their age and divide it into 3 parts to find out Alvin's and Richard's age cause Richard's age is 2x Alvin's age.
36 divided by 3 =12(Alvin's age)
Alvin is 12 years old.
Richard's age is 2x Alvin's age so to find out Richard's age,you must times Alvin's age by 2.
12x2=24
Richard is 24 years old.
To check,just add the two person age together.
24+12=36

Hope you understand!!

Answer 3

Let Alvin's age is: x
Richard's age will be: 2x (because, Richard is twice as old as Alvin)

x + 2x = 36 (because, sum of their ages is 36)
=> 3x= 36
=> x=12

Therefore, Alvin's age=x=12
Richard's age=2x= 2x12=24

Answer 4

let the age of Alvin be x
Richard=2x
2x+x=36
3x=36
dividing by 3
x=12
therefore age of Alvin=12 and that of Richard=24

Answer 5

R = 2A
R + A = 36

3A = 36
A = 12
R = 24

Are you really trying, or just looking for answers?

Answer 6

24,12