Graphing equations and plotting at least five points.?

Question

How do I plot x - 2y=6 if I do not know what x is or what y is? How do you go about answering this question. Again need step by step explanation. Thanks

Answer 1

Just pick any five values of x. say you pick -2,-1,0,1,2,3. First plug in -2 into x-2y=6.
so -2-2y=6
-2y=8
y=-4
then, plot (-2,-4)
repeat this for all 5 values that you picked and draw a line through the points. There is the graph and you have 5 points.

Answer 2

solve for y

(x-6=2y) divide the whole eq by 2 to get y
equals..
y=x/2-3

get the values of x and y

place values of x on the table of values and solve for y (substitute values of x to solve for y)

ex. x y
2 -2 ; ex. y= 2/2-3 y=-2
1 -2and1/2
0 -3
-1 -3and1/2
-2 -4

hope that helps..

;D

then to graph,

plot the x and y values on the graph

Answer 3

x - 2y = 6
-2y = -x + 6
y = (1/2)x - 3

Now just plug in values for x so that you can get y

to graph this, go to http://www.calculator.com/calcs/GCalc.html

and only type in (1/2)x - 3, then click enter on the keyboard. You can also get there through www.calculator.com

Answer 4

you subtract 3x from 2 that you cant becuase its a varible so it finally ends up being 2-3x. so your finished equation is y=2-3x. now you need to locate your x and y corrdinates. to locate your x, change your 0 for y. now make certain the equation that may be 0=2-3x. for y, change 0 for x. now with your x intercept, your corrdinates for which may be the answer and 0 so (-answer-, 0) and on your y interecept (0,-answer) graph!

Answer 5

draw a horizontal line through y=6/2=3 on y axis.

it does not say anything about x, so it could be any x (but y is still 3), and that's exactly what you had drawn.

Answer 6

x - 2y=6
it supposed:
For x = -3; y = -4,5 => (-3; -4,5)
For x = -2; y = -4 => (-2; -4)
For x = -1; y = -3,5 => (-1; -3,5)
For x = 0; y = -3 => (0; -3)
For x = 1; y = -2,5 => (1; -2,5)
For x = 2; y = -2 => (2; -2)
For x = 3; y = -1,5 => (3; -1,5)
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