how do i simplify an expression and write an answer without negative exponents?

Answer 1

x^(-n) = 1/(x^n)
Likewise,
1/[x^(-n)] = x^n

Ex. x^(-3) = 1/[x^3]
1/[x^(-4)] = x^4

Answer 2

The only thing to remember about negative exponents is that whenever you move them across the dividing line of a fraction, they change from positive to negative, or vice versa. For example, x^(-3) { 'x to the power of -3' )

First, we realize that x^(-3) is the same as x^(-3)/1. Thus, like we said above, we move the x^(-3) across the division symbol, and it changes from negative to positive, i.e. 1/(x^3).

In general, any number to a negative exponent is the same as one over that same number to its positive exponent.

Example #2:

[m^(3)n^(-3)]/[(2^(-1) (x^9)]

To convert this all into positive exponents, we note the negative exponents and move them across the division symbol. Let's start with the n^(-3),

[m^3] / [2^(-1) (n^3) (x^9)]

And then let's continue with the 2^(-1). Note that when we do this, it becomes 2^1, which is just 2.

2(m^3) / [ (n^3) (x^9) ]

Notice that it works both ways, that it doesn't matter whether you're bringing a negative exponent up from the bottom, or down from the top; the exponent always changes sign.

The following is an example where you should NOT move the negative exponent.

[x^(-3) + m^(3)] / [n^5]

It would be an invalid step to move x^(-3) to the bottom, because that only works with a PRODUCT (i.e. multiplication of terms). The answer would NOT be

(m^(3)) / [x^3 + n^5] <----- WRONG WRONG WRONG ALERT.

If you want to know how to solve such a problem, what you'd first do is express the term itself as a positive exponent, as follows:

[x^(-3) + m^(3)] / [n^5]

x^(-3) = 1/x^3, so

[ (1/x^3) + m^3 ] / [n^5]

Multiply top and bottom by x^3, to get

[1 + x^3 m^3 ] / [x^3 n^5]

Answer 3

10 raised to a negative 2(-2) can be written as 1 over 100(1\100) as for any negative exponent.

Answer 4

a^(-b) = 1/a^b

Answer 5

because the emblem contained in the brackets is multiplication..you'll get the potential into the brackets..it is going to develop into enable y=(a^4*c^-5/3) y={(a^4)/(c^5/3)} The detrimental signal contained in the potential skill the reciprocal....at the same time as the denominator contained in the potential represents the nth root Ex:in this question,that is dice root of c^5(it truly isn't any longer required in this particular question yet many ppl have a tendency to confuse) desire this helps.................