In ΔABC, given that a = 17m, b = 18m, and c = 26m, find the angles of A, B, and C.?

Question

In ΔABC, given that a = 17m, b = 18m, and c = 26m, find the angles of A, B, and C.

Answer 1

Best way to do this is using the Law of Cosines. Check here:
http://mathworld.wolfram.com/LawofCosines.html

For your specific problem, A= 40.57 degrees
B=43.52 degrees, and C=95.91 degrees.

Steve

Answer 2

Use the law of cosines.
c^2 = a^2 + b^2 -2ab(cosC)
Plug in 26 for c, 18 for b, and 17 for a.
676 = 324 + 280 - 612*cosC
cosC = -7/68
C = 95.9 degrees

Do it again for b.
324 = 676 + 280 - 884cosB
B = 44.4 degrees.

Since the angles of a triangle add up to 180 degrees, find the angle A with this equation: 180 - 44.4 - 95.9 = A
Therefore, A = 39.7, B = 44.4, and C = 95.9

Answer 3

Not to put anyone down here or anything; but the correct answer is:

a = 49.3
b = 52.2
&
c = 75.4

A triangle is 180 degrees. You set the equation equal to180. ( 17m + 18m + 26m = 180 ) Add like terms... ( 61m = 180 ) Divide 180 by 61. It comes out to 2.9. Add 2.9 in for m, so... 17(2.9) = 49.3; 18(2.9) = 52.2 + 26(2.9) = 75.4. Add all those up and you get 176.9 .

That is the closest answer you will get before going any farther into the decimals.

Geometry ... its a beast.

Hope this helps.

Answer 4

A = 20 B = 62 C = 98

let side a = the base
let C = the top angle

draw an imaginary line from angle C to create 2 right triangles and solve each right triangle.

let the left triangle be y and the right triangle be z

y:
26^2 - 8.5^2 = 24.6^2 note 8.5 is one half of 17 to form base of the right triangles

f(A) = arc tan(24.6/8.5) round to whole number = 20

part of angle C = 180 - (90 + 20) = 70

18^2 - 8.5^2 = 15.9 ^2

f(B) = arc tan(15.9/8.5) = 62

other part of C = 180 - (90 + 62) = 28

C = 70 + 62 = 98

A + B + C = 180: 20 + 60 + 98 = 180

Answer 5

Use the cosine law to find the angles:
a^2=b^2+c^2-2bc cosA
with the variations for angle B and C so the answers are angle A=40.6 degrees, B=43.5 degrees and C=95.9 degrees

Answer 6

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Answer 7

use cosine law to find the angle btw, a&b,,

c^2 = a^2 + b^2 - 2a.b. (cos A)

putting values in there u get
95.9

use sine law to get the angle between b & c

or i would rather use cosine again.. because i like cosine law!
a^2 = b^2 + c^2 - 2.b.c (cos B)

B= 40.57

C = 180 - A- B
=43.53

Answer 8

A= 40.569697230356
B=43.521740923667
C=95.908561845977