Use cylindrical shells to find the volume of the soid that results when the region enclosed by y^2=8x and x=2 is revolved about the line x=4
I got the answer (64(4square root 2-1)pie)/5 , is that correct??
2006-12-16 14:08:25 · 2 answers · asked by daniel_hower 1 in Science & Mathematics ➔ Mathematics
I tried this problem and I didn't get your answer.
If I'm reading this right, y= +/- sqrt (8x), which is the height, and the radius is 4-x, so it would be (sorry but it's almost impossible to type):
4pi (integral from 0 to 2) (4-x) * (8x)^1/2 * dx
I'm pretty sure it's 4pi instead of 2pi because the height is y= positive and negative sqrt(8x), so you simplify it by doubling it.
If you do this and integrate, (assuming I didn't mess up) then you get:
4pi (8-2)(128/3) - (0) = 1024pi
I may have made a mistake somewhere in there but I'm mildly confident about this answer.
2006-12-16 15:08:37 · answer #1 · answered by feret182 2 · 0⤊ 0⤋
Someone solved this problem just yesterday!
2006-12-16 22:19:37 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋