Chemistry help please...?

0 ⤊

Chemistry help please...?

When 0.387 grams of chromium, Cr(s) is heated in excess Cl2(g), 1.178 grams of a single solid compound is formed. Assuming that all the chromium reacts, what is the empirical formula of the compound?

Answer is CrCl3, but I don't know how to solve it, can someone help me.... thanks..

2006-12-16 11:57:53 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

The 0.387 grams of chromium have reacted with 0.791 grams of chlorine. Determine the number of moles of each.

0.387/51.99 = 0.0074 mol Chromium
0.791/35.45 =0.0223 mol of chlorine

0.0074/0.0074 = 1 Unit of Chromium

0.0223/0.0074 = 3 Units of Chlorine

Formula = CrCl3

2006-12-16 13:38:21 · answer #1 · answered by docrider28 4 · 0⤊ 0⤋

Dont click on man

2006-12-16 11:59:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋