find the rectangular coordinates of the point whose polar coordinates are (3,5pi/6)???

Answer 1

(r,θ) = (3,5π/6)

x = rcosθ
y = rsinθ

sin(5π/6) = 1/2
cos(5π/6) = -(√3)/2

x = 3*[-(√3)/2] = -3√3/2
y = 3(1/2) = 3/2

(x,y) = (-3√3/2,3/2) = (2.598,1.5)

Answer 2

cos theta=cos 5pi/6=-rt3/2
sin theta=1/2
x=rcos theta=-3rt3/2
y=r sintheta=3/2

Answer 3

x = 4cos@
y = 4sin@