2006-12-16 11:27:10 · 7 answers · asked by hans d 1 in Science & Mathematics ➔ Mathematics
r cos theta = 5
2006-12-16 11:30:55 · answer #1 · answered by Joni DaNerd 6 · 0⤊ 1⤋
in ploar co-odrinates
x = r cos t
y = r sin t
from the given condition r cos t = 5
2006-12-16 11:35:51 · answer #2 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
r = sqrt(x^2 + y^2) t = arctan(y / x) a) r = sqrt(5^2 + (-5)^2) = sqrt(25 + 25) = sqrt(2 * 25) = 5 * sqrt(2) t = arctan(-5 / 5) = arctan(-a million) = 3pi/4 (5 * sqrt(2) , 3pi/4) b) r = sqrt((-3)^2 + (3 * sqrt(3))^2) = sqrt(9 + 27) = sqrt(36) = 6 t = arctan(3 * sqrt(3) / (-3)) = arctan(-sqrt(3)) = 2pi/3 (6 , 2pi/3) c) r = sqrt((-4)^2 + (-4 * sqrt(3)) / 3)) = sqrt(sixteen + 40 8) = 8 t = arctan(-4 / (-4sqrt(3) / 3)) = arctan(3 / sqrt(3)) = arctan(sqrt(3)) = pi/3 , 4pi/3 for the clarification that we are in Q3, t = 4pi/3 (8 , 4pi/3)
2016-12-11 10:34:20 · answer #3 · answered by Erika 4 · 0⤊ 0⤋
rcost=5 .
2006-12-16 12:03:46 · answer #4 · answered by tablecloth 1 · 1⤊ 0⤋
rcost=5
.
2006-12-16 14:19:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x = r cos θ
r = x/cos θ = 5/cos θ
2006-12-16 12:09:20 · answer #6 · answered by Northstar 7 · 0⤊ 0⤋
r=5/cos((theta))
2006-12-16 11:32:21 · answer #7 · answered by Stirling 2 · 0⤊ 0⤋