if n= 3^x + 3^x + 3^x, what is the value of n^2? Show work.?

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2006-12-16 11:14:21 · 5 answers · asked by Wade N 1 in Science & Mathematics ➔ Mathematics

n=3^x+3^x+3^x=3*3^x
n^2=3^2*3^2x
=3^(2x+2)
3^{2(x+1)}

2006-12-16 11:20:36 · answer #1 · answered by raj 7 · 0⤊ 2⤋

n = 3^x + 3^x + 3^x

so n = 3(3^x) = 3^(x+1)

and n^2 = 3^2(x+1) = 3^(2x + 2)

2006-12-16 19:22:00 · answer #2 · answered by Stewart H 4 · 2⤊ 0⤋

n= 3^x + 3^x + 3^x=3^(x+1)
n^2=3^(2x+2)

2006-12-16 22:01:16 · answer #3 · answered by yupchagee 7 · 1⤊ 0⤋

3^x + 3^x + 3^x = 9^x = n therefore n^2 = 9^2x

2006-12-16 19:39:14 · answer #4 · answered by tropicalturbodave 5 · 0⤊ 1⤋

n = 9^x
n^2 = (9^x)^2
n^2 = 9^2x

2006-12-16 19:41:18 · answer #5 · answered by Renaud 3 · 0⤊ 1⤋