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How do you write the following equation in standard form 1/2x - 9=0 but using only integers. I don't understand this question either, HELP! If possible I need step by step so that I can better understand this one as well.

2006-12-16 09:44:25 · 8 answers · asked by 2good4hem 3 in Science & Mathematics Mathematics

8 answers

that would be 1x + 0y + (-9) = 0. For explanation, see email.

2006-12-17 10:55:12 · answer #1 · answered by Joni DaNerd 6 · 0 0

the standard form is Ax+By+C=0
here 1/2x-9=0
multiplying by 2
x-18=0
adding18
x=18 is the equation in the standard form

2006-12-16 10:14:40 · answer #2 · answered by raj 7 · 0 0

Ax+By=C is the standard form.

First add 9 to both sides of the equation.

1/2x=9 * can not have a fraction for your A.

So, multiply the whole equation by 2.
2(1/2x=9)

The answer is x=18

2006-12-17 05:53:12 · answer #3 · answered by wheels 2 · 0 0

as previously stated, it's Ax+By+C=0, where A, B, and C are integers. to get to that form: start by multiplying out the right side, so y-5=(3/2)x+6 then subtract (3/2)x from both sides, y-(3/2)x-5=6 then subtract 6, y-(3/2)x-5-6=0 and finally just tidy it up, -(3/2)x+y-11=0

2016-05-22 23:58:06 · answer #4 · answered by Anonymous · 0 0

I think Raj is right but make the equation equal 0 so
x - 18 = 0 would be the answer.

2006-12-16 10:37:58 · answer #5 · answered by CAM1122 3 · 0 0

standard form is
1/2x = 9
1= 18x
x = 1/18
x-1/18=0 is the standard form

2006-12-16 09:48:45 · answer #6 · answered by ghakh 3 · 0 0

1/2x - 9=0

1/2x = 9 multiply both sides by two

x = 18

I believe this is the answer!

2006-12-16 09:50:07 · answer #7 · answered by ___ 4 · 0 0

1/2x - 9 = 0

2(1/2x) - 2(9) = 2(0)

x - 18 = 0

- - - - -s-

2006-12-16 09:53:09 · answer #8 · answered by SAMUEL D 7 · 1 0

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