Clark Elementary School has decided to buy a new copying machine. One of the selling points of the new machine is that the manufacturer advertised that the school can expect about 2 paper jams per 1000 copies. After six months, the faculty wanted to see how the copier was actually doing. They had run 42,164 copies and had encountered 96 paper jams.
2006-12-16 09:09:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
42164:96::1000:x
96000=42164x
x=96000/42164
=2.28
so the claims are false.
more papres are getting jammed than stipulated
2006-12-16 09:14:30 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Divide the number of copies by the number of paper jams. Then do the same thing with the advertised values (1000 copies/2 jams). This will give you the number of copies per jam ratio.
Compare the two ratios to see if the advertised number of jams is more or less than the actual number of jams.
2006-12-16 09:14:12 · answer #2 · answered by mathsmile 2 · 0⤊ 0⤋
They should have had 42164/500 paper jams, about 84. So looks like they were ripped off. Or they weren't careful when loading the trays, or had the machine running in a very dusty area or something. We may never know.
2006-12-16 09:14:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2006-12-16 09:15:38 · answer #4 · answered by modulo_function 7 · 0⤊ 0⤋