Ok I heard this from some one else and I really don't get how it works. Here it goes:
3 studens go an buy a second hand car.
The car is $30. So they all pay $10.
After they leave, the former car owner decides to give them back $5. So he sends his helper to find them and give them the $5 back.
The helper decides to keep $2 and gives $3 back to the students.
Now all of the students have paid 9dollars. it you take the student money $9 X 3 = $27 + de $2 from the helper = $29! where did the $1 dollar go? I now you can't buy a car for 30 dollars, but it would be the same if you made it in to 30.000 dollars. That is not the point. I just want to know where the $1 went.
2006-12-16 07:48:25 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm going to have to copy this answer and keep it. I see this question, or a variation of it every week.
The students did not pay 9 dollars apiece for the car, they paid $8.33 1/3 apiece for the car, or a total of 25 dollars.
Of the 30 dollars, 25 was for payment of the car, 3 dollars was returned to the students and the rotten helper got 2 dollars.
2006-12-16 07:57:40 · answer #1 · answered by Walking Man 6 · 0⤊ 0⤋
The error is in this logic"t you take the student money $9 X 3 = $27 + de $2 from the helper = $29!" It should say the student paid $27; $2 went to the helper, leaving the dealer with $25.
Because $25 for the car, + $2 for the helper + $3 credit to the student make up how the original $30 was divided.
2006-12-16 16:56:07 · answer #2 · answered by Renaud 3 · 0⤊ 0⤋
Well, actually it is $27 MINUS 2. That is, each of the students paid $9. That comes out to $27. But the dealer only got $25. Where did the other $2 go? To the helper!
2006-12-16 15:52:20 · answer #3 · answered by firefly 6 · 0⤊ 0⤋
This 1 is older than I am. I think Aristotle came up with it.
each student paid $9. 3*$9=$27. The former owner got $25. The helper got $2
$2+$25=$27 received = $27 paid.
2006-12-16 15:51:51 · answer #4 · answered by yupchagee 7 · 2⤊ 0⤋
each did pay $9.
They paid $30 to start got $5 back = $25
Left $2
$25+$2 = $27
$27/3 = $9
2006-12-16 16:08:03 · answer #5 · answered by Modus Operandi 6 · 0⤊ 0⤋
u don't times 9 by 3, if they have 30$ and he gives them 5$ back thats 25$, but they really only get 3$ back because the helper keeps 2$ ,thats 25 + 3 thats 28, 28$ + the 2$ helper took thats 30$ right? you must not have done to well in math class did you?
2006-12-16 16:09:35 · answer #6 · answered by remaninkool 1 · 0⤊ 0⤋
The students got $3 back.
The helper took $2.
The owner received $25.
$3+$2+$25=$30
The students didn't really pay $9 each because the helper took $2. They actually paid $8.33 each.
This was pretty tricky.
2006-12-16 16:00:26 · answer #7 · answered by Jacques 5 · 0⤊ 1⤋
Dude, you're adding it wrong. Each guy paid $9... That's $27 ($25 for the owner & $2 in the guys' pocket). Plus the $1 that each student got equals $30. You're counting the two dollars twice.
2006-12-16 15:55:11 · answer #8 · answered by Xceed One 3 · 0⤊ 0⤋
Each student BELIEVES he paid $9 for the car. In reality each student paid $8.3333 for the car and $.66666 to the helper.
$8.33333 * 3 = $25
$.66666 * 3 = $2
$25 + $2 = $27
2006-12-16 16:01:31 · answer #9 · answered by Brad 4 · 0⤊ 0⤋
Benoit posed the "solution" -- maybe a little too tersely.
Look at it this way: The dealer gives his lackey $10, but this time the lackey holds out $7, giving each of the buyers one $1. Are you gonna take the student perspective again? 9x3 = 27 and go adding the $7
(If you do, I have a London Bridge to sell you.)
2006-12-16 16:08:53 · answer #10 · answered by answerING 6 · 0⤊ 0⤋