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You have five people.
Two dice.
One pack of cards.

How do you think you could use these things to establish who in the group has the same birth date, or what are the chances those in the group, or some of those group have the same birth date? (month and date only, not year).

2006-12-16 07:36:41 · 4 answers · asked by Laura 1 in Science & Mathematics Mathematics

I don't know Bao, why do you care about this question? You're the only the one who knows the answer to that.

2006-12-16 07:46:24 · update #1

4 answers

Assuming no one is born Feb 29,

There are 365 days that could be birthdays.

The chance that no one shares the same birthday is:

1 * (364/365) * (363/365) * (362/365) * (361/365)

The idea, from probabilty, is that person one is born on any day. The second person could be born on any other day of the year, the third, any but the birthdays or the first two. So this will give the probability that no one shares the same birthday.

Subtract this value from 1, and you will get the probability of having at least one birthday shared.

The computation is left as an exercise for the reader... or you can just open up calc on your machine and figure it out yourself.

2006-12-16 07:54:28 · answer #1 · answered by John T 6 · 0 0

The die would represent the months. Since each dice has a maximum of 6 dots, there's a maximum of 12 dots to represent the months, January through December.

Use the cards to represent the date. Ace would be the first of the month; 2 would be the 2nd, etc. Jack could be 11th, Queen could be 12th, and King would be 13th. Combine cards to get dates greater than the 13th. For example, a 2 of hearts and an 8 of clubs could represent the 28th.

2006-12-16 15:48:18 · answer #2 · answered by Anonymous :) 5 · 0 0

I have no idea you could ask them to pick a card .......

2006-12-16 15:40:44 · answer #3 · answered by Anonymous · 0 3

Why do I care?

2006-12-16 15:42:06 · answer #4 · answered by Bao L 3 · 0 5

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