Trigonometry help?

Question

Must show wok

1). A man standing on top of a building sees an automobile on a street
below him. The angle of depression is 36°22'. If his eye is 550ft above
the level of the automobile,how far is the automobile from him?

2).When the sun's angle of elevation is 30° the shadow of a post is 6
ft longer than when the angle is 45°. Find the height of the post."

Answer 1

1
sin(36degrees 22 seconds)=550/d
where d is the distance

2.
x is the shadow when the elevation is 45
h is the height of the post

Tan(45)=h/x
x=h

Also
Tan(30)=h/(x+6)
since h=x
tan(30)*h+tan(30)*6=h
tan(30)*6/(1-tan(30))=h
=8.2 ft

j

Answer 2

1) tan(36°22') = 550/d
d = 550/tan(36°22') ~ 746.9 ft

2) tan(45°) = y/x -> x = y/tan(45°)
tan(30°) = y/(x + 6) -> x = y/tan(30°) - 6

y/tan(45°) = y/tan(30°) - 6
tan(30°)y = tan(45°)y - 6tan(45°)tan(30°)
y - tan(30°)y = 6tan(30°)
y = 6tan(30°)/(1 - tan(30°)) ~ 8.196 ft