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"When solid sodium bicarbonate is heated in a test tube, an invisible gas, carbon dioxide is released into the surrounding air. Water condenses at the mouth of the test tube and a while solid residue, sodium carbonate, remains behind in the bottom of the test tube"
Is this one written as:
2NaHCO3--> Na2CO3 + CO2 + H2O?

What's the product of
Sodium hydroxide + Phenolphthalein + Hydrochloric acid?

Ethyl alcohol + water + [heat or the lighting of the alcohol with a butane safety lighter (would this be O2?)]??

:)

2006-12-16 06:36:30 · 3 answers · asked by Krysie 2 in Science & Mathematics Chemistry

3 answers

1.In the first reaction the water H2O is crystal water and is not a product from the reaction.2. In the second reaction : NaOH + HCl > NaCl +H2O (The phenolphthalein acts as a indicator so you will know if the solution is pH-neutral ) 3.There is no reaction between ethyl alcohol and water.The gas you see is the gas that is dissolved in the water. Try again with cooked and cooled water and you will see the difference.

2006-12-16 07:09:38 · answer #1 · answered by Anonymous · 0 0

The sodium bicarb formula needs to be balanced. Make sure you have the same amount of atoms on each side of the equation. For example you have 6 O's on the right, but 9 on the left.

Any reaction of a base (sodium hydroxide NaOH) and an acid (hydrochloric acid HCl) will give a salt + water (NaCl + H20 table salt and water in this case). Not sure what phenolphthalein will do when added.

The alcohol does give off CO2 when heated. The water only weakens the reaction. And O2 doesn't explode, only makes fires burn better.

2006-12-16 15:08:40 · answer #2 · answered by pdxman1964 1 · 0 0

first of all if you release o2 you'll blow your hand off. if gases are released go with either co2 or h2. they're a lot safer - easier to produce (means it's gonna happen) and fairly stable.

for the NaOH you need to look up indicators and what color they turn and why they work. it'll be easy then

2006-12-16 14:40:08 · answer #3 · answered by shiara_blade 6 · 0 0

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