2006-12-16 05:30:06 · 2 answers · asked by bethanie3 1 in Science & Mathematics ➔ Chemistry
No....you cannot relate masses in a chemical reaction, you have to do it by moles.
So, if no of moles = mass/molar mass,
you have 8 / 2 = 4 moles of hydrogen
and 2 / 32 = 0.0625 moles of oxygen.
Since 2H2 + O2 --> 2H2O
the oxygen is the limiting reagent, and so you should get no more than 0.0625 x 2 = 0.125 moles of water.
Mass = no of moles x molar mass = 0.125 x 18 =2.25g of water (theoretical yield)
2006-12-16 05:37:00 · answer #1 · answered by claudeaf 3 · 1⤊ 0⤋
No. You have 8/2 moles H2, but only 2/32 moles O2. So there is not nearly enough O2 for all the H2 to react.
The theoretical mass of product will be 2/32 x 2 x 18g. Most of the hydrogen will not react.
2006-12-16 05:35:38 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋