2006-12-16 05:18:19 · 13 answers · asked by Akira B 1 in Science & Mathematics ➔ Mathematics
(x + 5)(2x - 1) = 0
x + 5 = 0 or
2x - 1 = 0
x = -5 or
x = 1/2
2006-12-16 05:21:32 · answer #1 · answered by Anonymous :) 5 · 1⤊ 0⤋
Factor as (2x-1)*(x+5)=0
Then use the zero product rule to set the pieces =0
2x-1=0 or x+5=0
Solve these to get:
x=1/2 or x=-5
2006-12-16 05:23:00 · answer #2 · answered by a_math_guy 5 · 1⤊ 0⤋
2x^2 + 9x - 5 = 0
Do factorization:
multiply 5 with 2 and then find a number like if we multiply it by any number we get 10 and if we subtract them we 9..
2x^2 + 10x - 1x - 5
2x(x + 5) -1 (x + 5)
(2x - 1) (x +5)
2x = 1 >> x = 1 / 2
x = - 5
2006-12-16 05:30:33 · answer #3 · answered by your pal 2 · 0⤊ 0⤋
2x^2 + 9x - 5 = 0
(2x - 1)(x + 5) = 0
2x - 1 = 0 or x + 5 = 0
2x = 1 (Divide both sides by 2)
x = 1/2
---------
x + 5 = 0 (Subtract 5 from both sides)
x = -5
x = 1/2 or x = -5
QED
2006-12-16 18:31:46 · answer #4 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
factor it first (2x-1)(x+5)
then set both of them to zero 2x-1=0 and x+5=0
then solve for x=1/2 and x=-5
2006-12-16 05:27:55 · answer #5 · answered by criminalinvestigator23 1 · 0⤊ 0⤋
1/2,-5
2006-12-16 05:25:07 · answer #6 · answered by avin 1 · 0⤊ 0⤋
2x^2+9x-5=0
2^2+10x-1x-5=0
2x(x+5)-1(x+5)=0
(2x-1)(x+5)=0
2x-1=0
2x=1
x=1/2
x+5=0
x=-5
Therefore, the valuses for x are, x=1/2 and x=-5
2006-12-16 05:28:28 · answer #7 · answered by angel 2 · 0⤊ 0⤋
x= negative 5 or x=1/2
2006-12-16 05:27:44 · answer #8 · answered by c c 1 · 0⤊ 0⤋
2x^2+9x-5=0
(2x-1)(x+5)=0
2x-1=0
x=1/2
x+5=0
x=-5
x=1/2, -5
2006-12-16 06:06:11 · answer #9 · answered by yupchagee 7 · 0⤊ 0⤋
2x^2+10x-x-5=0
2x(x+5)-1(x+5)=0
(x+5)(2x-1)=0
x+5=0 x=-5
2x-1=0
x=1/2
so x=1/2 or -5
2006-12-16 05:22:13 · answer #10 · answered by raj 7 · 2⤊ 0⤋