if these are your answers
x < 20
x < -20
x < 0
x < -100
how would you solve that and if you do solve it how did you get your answer
2006-12-16 01:36:00 · 8 answers · asked by cr@ZY_$3XY_c00l 2 in Science & Mathematics ➔ Mathematics
This needs basic knowledge and skill in manipulating linear inequalities: use the same rules you use for equations except when dividing and multiplying by negative numbers, then you need to switch signs.
Thus,
x < 10 -10=0
x<0
2006-12-16 02:14:42 · answer #1 · answered by mulla sadra 3 · 1⤊ 0⤋
10 - 5x + 6x < 10
10 + x < 10
10 + x - 10 < 10 - 10
x < 0
2006-12-16 10:59:28 · answer #2 · answered by Ranna Renni 2 · 1⤊ 0⤋
10 - 5x + 6x < 10 combine like terms
10+x<10 subtract 10 from each side
x<0
2006-12-16 14:24:33 · answer #3 · answered by yupchagee 7 · 1⤊ 0⤋
Combine like terms:
x+10<10
Subtract 10 on both sides:
x<0
2006-12-16 13:51:29 · answer #4 · answered by Anonymous · 1⤊ 0⤋
10 - 5x + 6x < 10
-5x+6x < 0 (adding 10 to both sides)
x < 0 (collecting terms)
You learned all this stuff last year. It didn't change while you were on vacation.
2006-12-16 13:02:36 · answer #5 · answered by Anonymous · 1⤊ 0⤋
10 - 5x +6x < 10
10 + x < 10
x < 10 - 10
x < 0
Doug
2006-12-16 10:12:33 · answer #6 · answered by doug_donaghue 7 · 1⤊ 0⤋
10-5x+6x<10(add the variables together)
10-x<10 (subract 10 n both sides)
-x<0 (multiply both sides by -1)
x<0 (this is youir answer)
2006-12-16 11:16:42 · answer #7 · answered by ♥KiYa♥ 3 · 1⤊ 0⤋
solve the same way as you solve an equation.
x<0
You have got a very interesting name indeed...
2006-12-16 10:20:28 · answer #8 · answered by math 2 · 1⤊ 0⤋