2006-12-15 22:27:13 · 25 answers · asked by tuk r 1 in Science & Mathematics ➔ Mathematics
Well, number that divide them all would be a divisor of their greatest common factor, which is the largest number that can divide them all without remainder.
Since the greatest common factor of 481 & 888 is 37 and since the greatest common factor of all is a divisor of 37 (1 or 37), we can check if all are divisible by 37. If they are, it is the greastest common factor.
It is indeed so.
481 = 37*13
888 = 37*24
1332 = 37*36
703 = 37*19
962 = 37*26
1295 = 37*35
So all the divisors of 37 will divide all numbers and these are 1 and 37 itself.
2006-12-16 01:46:00 · answer #1 · answered by mulla sadra 3 · 0⤊ 0⤋
The number by which 481, 888, 1332, 703, 962 and 1295 can be divided without leaving a reminder is 37.
481 devided by 37 is 13,i
888 divided by 37 is 24,
1332 divided by 37 is 36,
703 divided by 37 is 19,
962 divided by 37 is 26, and
1295 divided by 37 is 35.
2006-12-15 23:07:13 · answer #2 · answered by samu88882003 1 · 0⤊ 0⤋
1
2006-12-15 22:30:01 · answer #3 · answered by sthrnduff 2 · 0⤊ 0⤋
They can all be divided by 37 without leaving a remainder.
481 = 37 * 13
888 = 37 * 2 * 2 * 2 * 3
1332 = 37 * 2 * 2 * 3 * 3
703 = 37 * 19
962 = 37 * 2 * 13
1295 = 37 * 5 * 7
2006-12-15 22:35:16 · answer #4 · answered by falzoon 7 · 0⤊ 0⤋
37
2006-12-16 02:20:26 · answer #5 · answered by Michael 2 · 0⤊ 0⤋
888, 1332, 962, 1295
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2006-12-16 01:39:30 · answer #6 · answered by aeiou 7 · 0⤊ 0⤋
37
2006-12-15 23:17:06 · answer #7 · answered by Anonymous · 0⤊ 0⤋
1 and 37
2006-12-15 22:45:08 · answer #8 · answered by crazydave 7 · 0⤊ 0⤋
37
2006-12-15 22:39:42 · answer #9 · answered by Anonymous · 0⤊ 0⤋
37
2006-12-15 22:39:04 · answer #10 · answered by Anonymous · 0⤊ 0⤋