how do I do this long algebra equation?

Question

Write an equation to answer this question: How many mL of a 67% solution should be added to make the solution 72% alcohal? Let x=
the number of mL of the 67% solution to be added. Solve the equation and write the answer to the question.

Answer 1

I would like to help you, but the question is very ambiguous. But still let me try.

This is what I understand,
We have a 67% Alcohol solution. We need to make it 72% Alcohol solution. You want to know how much Alcohol should be added to make it 72%. If that is the question, then the following equation should help you,

0.67(x) + (y) = 0.72(x+y)
0.28y = 0.05 x
y = 0.05/0.28 * x
y = 0.17851x

This means that for every 100 mL of 62% Alcohol, add 17.851 mL of 100% Alcohol to make the resultant mixture, 72% Alcohol.

Answer 2

The question is unclear. How many mL of a 67% solution should be added to what?

Answer 3

To get to 72% alcohol from 67% alcohol you need to add a solution which is more than 72% alcohol, or you need to add the 67% solution to a solution greater than 72%.

Answer 4

2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+... (i assume the (4x+4)2 potential squared?) -5 + 7x + 16x^2 + 32x + 16 = -11x + 12 - 24x + 30x + 13x - sixty 5 - 7 16x^2 + 39x + 11 = 8x - 60 16x^2 + 31x + seventy one = 0 Sorry yet have I made a mistake right here? i imagine your own paintings would want checked.

Answer 5

x=57397 / 63725 + 3563= E =MC2 = 6723 * 536 - 735 / 62748% there you have it. You have to figure out the whole formula.