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11.2 litres is half a mole of CO2 (at STP), so that would require half a mole of CaCO3 - ie 50g.

But your sample is only 95% pure, so multiply 50 by 100/95.

2006-12-15 21:09:57 · answer #1 · answered by Gervald F 7 · 0 0

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