1g of titanium reacts with chlorine to give 3.22g compound.What is the valency of titanium?

Question

atomic weight of titanium is 48

Answer 1

Let k be the valency of titanium. The the formula of the compound will be TiCl_k and its molecular mass 48+k*35.45.

Therefore (48+35.45 k)/48 = 3.22 /1.
Solve for k to find k=3.006.

Answer 2

12

Answer 3

Since chlorine and carbon are in excess, we can only have as much product as TiO2 allows (TiO2 is the limiting reactant). First you must balance the equation: TiO2 + 2 Cl2 + 2 C ----> TiCl4 + 2 CO Next, we find the number of moles of TiO2 from the information you provided about the mass. 50.0g TiO2 * (1 mol TiO2/ 79.88g TiO2) = 0.626 mol TiO2 Next, use stoichiometrically equivalent molar ratios to say that 1 mol of TiO2 is equivalent to TiC;4, as the balanced equation shows: 0.626 mol TiO2 * (1 mol TiCl4 / 1 mol TiO2) = 0.626 mol TiCl4 Now, we find out the mass of TiCl4 in 0.626 mol TiCl4: 0.626 mol TiCl4 * (189.68 g TiCl4 / 1 mol TiCl4) = 118.74 g TiCl4. This is called the theoretical yield. As you probably already know, we have a problem. We got 55.0g, not 118.74 g. So let's calculate the percent yield using the formula: (actual yield / theoretical yield) * 100 (55.0g TiCl4/ 118.74g TiCl4) * 100 = 46.3% This seems low, and it should be. Most often the actual yield is much less do to measurement errors, side reactions, etc. Hope this helps!

Answer 4

1/3

Answer 5

The equation would be
xTi + yCl => Tix Cly
we can figure x (moles of Ti) divide by At Wt!!!
we can figure y (moles of Cl) {we can ignore the fact that the Cl starts off as Cl2}
3.22-1 = g of Cl {or g of Cl2, same thing, essentially*}
so we know the moles of Ti and Cl AND we should know that CL will almost always be monovalent (-1)
this means that the ratio of y/x gives the valency directly

example if 5 moles of Cl reacted with one mole of Zn then the ration would be 5:1 or Zn would be pentavalent (+5)
if 2.33 moles of CL reacted with 0.3 moles of Cx (new element!) Cx would be =7 = 2.33/0.3

you do Ti

*note that 5 moles of CL is 2.5 moles of Cl2 but using the valency of Cl2 is the wrong way to go.